Question on finding cartesian equation of a plane(general equations of a plane) Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Find an equation of the planeConverting a plane from Cartesian to ParametricRelation, Function and Equation… Cartesian Plane and GraphEquation of a plane given one point and two planesEquation of plane perpendicular to given planeEquation of a PlaneForm the equation of a plane, given 2 points and a parallel straight linevector equation of a plane that contains a point P0 and its perpendicular uXvTrouble expressing general form of the plane equationFinding an equation of a plane through the origin that is parallel to a given plane and parallel to a line.
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Question on finding cartesian equation of a plane(general equations of a plane)
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Find an equation of the planeConverting a plane from Cartesian to ParametricRelation, Function and Equation… Cartesian Plane and GraphEquation of a plane given one point and two planesEquation of plane perpendicular to given planeEquation of a PlaneForm the equation of a plane, given 2 points and a parallel straight linevector equation of a plane that contains a point P0 and its perpendicular uXvTrouble expressing general form of the plane equationFinding an equation of a plane through the origin that is parallel to a given plane and parallel to a line.
$begingroup$
Given the equation of a plane $5x+2y-z+22=0$ ,Find the vector $vec V$ perpendicular to the plane and point $P_o(x_o,y_o,z_o)$ on the plane ?
Trying Solutions:
Since the general equation is $Ax+By+Cz=D$ Where $D=Ax_o+By_o+Cz_o$
In the above $equation$, I found the $vec V$ as $vec V=5i+2j-k$
While $D=-22$ , hence I tried finding the point $P_o$ in the equation as $5x_o+2y_o-z_o=-22$
and am stuck at this point ?
Any help ?
Edit
The teacher gave this question in reverse where we were finding the $equation$ of the cartesian plane , and the $P_o(-3,0,7)$
Is it must I get these points ?
algebra-precalculus analytic-geometry
asked Apr 1 at 6:56
Yasir MKYasir MK
114
$endgroup$
add a comment |
$begingroup$
Given the equation of a plane $5x+2y-z+22=0$ ,Find the vector $vec V$ perpendicular to the plane and point $P_o(x_o,y_o,z_o)$ on the plane ?
Trying Solutions:
Since the general equation is $Ax+By+Cz=D$ Where $D=Ax_o+By_o+Cz_o$
In the above $equation$, I found the $vec V$ as $vec V=5i+2j-k$
While $D=-22$ , hence I tried finding the point $P_o$ in the equation as $5x_o+2y_o-z_o=-22$
and am stuck at this point ?
Any help ?
Edit
The teacher gave this question in reverse where we were finding the $equation$ of the cartesian plane , and the $P_o(-3,0,7)$
Is it must I get these points ?
algebra-precalculus analytic-geometry
asked Apr 1 at 6:56
Yasir MKYasir MK
114
$endgroup$
$begingroup$
Any point on the plane will do. Try setting two of the variables to zero.
$endgroup$
– amd
Apr 1 at 6:57
$begingroup$
Well one valid point is $(-2,-1,0)$
$endgroup$
– Peter Foreman
Apr 1 at 6:58
add a comment |
$begingroup$
Given the equation of a plane $5x+2y-z+22=0$ ,Find the vector $vec V$ perpendicular to the plane and point $P_o(x_o,y_o,z_o)$ on the plane ?
Trying Solutions:
Since the general equation is $Ax+By+Cz=D$ Where $D=Ax_o+By_o+Cz_o$
In the above $equation$, I found the $vec V$ as $vec V=5i+2j-k$
While $D=-22$ , hence I tried finding the point $P_o$ in the equation as $5x_o+2y_o-z_o=-22$
and am stuck at this point ?
Any help ?
Edit
The teacher gave this question in reverse where we were finding the $equation$ of the cartesian plane , and the $P_o(-3,0,7)$
Is it must I get these points ?
algebra-precalculus analytic-geometry
asked Apr 1 at 6:56
Yasir MKYasir MK
114
$endgroup$
Given the equation of a plane $5x+2y-z+22=0$ ,Find the vector $vec V$ perpendicular to the plane and point $P_o(x_o,y_o,z_o)$ on the plane ?
Trying Solutions:
Since the general equation is $Ax+By+Cz=D$ Where $D=Ax_o+By_o+Cz_o$
In the above $equation$, I found the $vec V$ as $vec V=5i+2j-k$
While $D=-22$ , hence I tried finding the point $P_o$ in the equation as $5x_o+2y_o-z_o=-22$
and am stuck at this point ?
Any help ?
Edit
The teacher gave this question in reverse where we were finding the $equation$ of the cartesian plane , and the $P_o(-3,0,7)$
Is it must I get these points ?
algebra-precalculus analytic-geometry
algebra-precalculus analytic-geometry
asked Apr 1 at 6:56
Yasir MKYasir MK
114
asked Apr 1 at 6:56
Yasir MKYasir MK
114
edited Apr 1 at 7:00
Yasir MK
asked Apr 1 at 6:56
Yasir MKYasir MK
114
asked Apr 1 at 6:56
Yasir MKYasir MK
114
asked Apr 1 at 6:56
Yasir MKYasir MK
114
114
$begingroup$
Any point on the plane will do. Try setting two of the variables to zero.
$endgroup$
– amd
Apr 1 at 6:57
$begingroup$
Well one valid point is $(-2,-1,0)$
$endgroup$
– Peter Foreman
Apr 1 at 6:58
add a comment |
$begingroup$
Any point on the plane will do. Try setting two of the variables to zero.
$endgroup$
– amd
Apr 1 at 6:57
$begingroup$
Well one valid point is $(-2,-1,0)$
$endgroup$
– Peter Foreman
Apr 1 at 6:58
$begingroup$
Any point on the plane will do. Try setting two of the variables to zero.
$endgroup$
– amd
Apr 1 at 6:57
$begingroup$
Any point on the plane will do. Try setting two of the variables to zero.
$endgroup$
– amd
Apr 1 at 6:57
$begingroup$
Well one valid point is $(-2,-1,0)$
$endgroup$
– Peter Foreman
Apr 1 at 6:58
$begingroup$
Well one valid point is $(-2,-1,0)$
$endgroup$
– Peter Foreman
Apr 1 at 6:58
add a comment |
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$begingroup$
Any point on the plane will do. Try setting two of the variables to zero.
$endgroup$
– amd
Apr 1 at 6:57
$begingroup$
Well one valid point is $(-2,-1,0)$
$endgroup$
– Peter Foreman
Apr 1 at 6:58