Backward Heat Equation with Transversality Condition Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)2D Heat Equation with special initial conditionRegularity of semilinear heat equationReducing heat equation into nondimensional formAsymptotic behavior of the heat equation with homogeneous Dirichlet boundary conditionEffective Boundary Condition for a Heat Equation with Variable ConductivityDifferential equation similar to “Heat equation” without $u(l,0)=0$ boundary conditionHeat equation with a positive coefficientheat equation maximum principle (clarification)1d-heat equation $L_infty$heat equation unbound in time

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Backward Heat Equation with Transversality Condition



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)2D Heat Equation with special initial conditionRegularity of semilinear heat equationReducing heat equation into nondimensional formAsymptotic behavior of the heat equation with homogeneous Dirichlet boundary conditionEffective Boundary Condition for a Heat Equation with Variable ConductivityDifferential equation similar to “Heat equation” without $u(l,0)=0$ boundary conditionHeat equation with a positive coefficientheat equation maximum principle (clarification)1d-heat equation $L_infty$heat equation unbound in time










1












$begingroup$


I have a backward parabolic equation of the form:



beginequation
W_eta + aW_xx - bW = 0
endequation



s.t.



beginequation
lim_eta rightarrow infty(x,eta) = g(x)
endequation



were $x in mathbbR$, $eta geqslant 0$, and $a,b$ are positive constants.



Applying the following transformations:



beginalign
W(x,eta) &= U(x,t)e^beta \
t &= aeta
endalign



we would get the backward heat equation below



beginequation
U_t = - U_xx
endequation



However, the transversality condition becomes a problem, since as $eta rightarrow infty$, $e^beta rightarrow infty$.



Usually, if the terminal condition is of the form



beginequation
W(x,H) = g(x)
endequation



with $H$ finite, we could "reverse" it, that is, we could apply the following transformation:



beginequation
nu = H - eta
endequation



to obtain



beginequation
-W_nu + aW_xx - bW = 0
endequation



s.t.



beginequation
W(x,0) = g(x)
endequation



which we can solve the traditional way (Fourier transform). However, as my terminal condition happens only at infinity I can't apply the reverse transformation above, thus I don't know how to overcome this problem. Any hint or reference?










share|cite|improve this question











$endgroup$











  • $begingroup$
    Have you tried solving the equation with $U(x,T)=g(x)$ and let $Ttoinfty$?
    $endgroup$
    – Dylan
    Apr 2 at 7:23










  • $begingroup$
    I have edited the question, now it reflects properly the problem I have.
    $endgroup$
    – Nicolas Pimentel de Souza
    Apr 2 at 14:48















1












$begingroup$


I have a backward parabolic equation of the form:



beginequation
W_eta + aW_xx - bW = 0
endequation



s.t.



beginequation
lim_eta rightarrow infty(x,eta) = g(x)
endequation



were $x in mathbbR$, $eta geqslant 0$, and $a,b$ are positive constants.



Applying the following transformations:



beginalign
W(x,eta) &= U(x,t)e^beta \
t &= aeta
endalign



we would get the backward heat equation below



beginequation
U_t = - U_xx
endequation



However, the transversality condition becomes a problem, since as $eta rightarrow infty$, $e^beta rightarrow infty$.



Usually, if the terminal condition is of the form



beginequation
W(x,H) = g(x)
endequation



with $H$ finite, we could "reverse" it, that is, we could apply the following transformation:



beginequation
nu = H - eta
endequation



to obtain



beginequation
-W_nu + aW_xx - bW = 0
endequation



s.t.



beginequation
W(x,0) = g(x)
endequation



which we can solve the traditional way (Fourier transform). However, as my terminal condition happens only at infinity I can't apply the reverse transformation above, thus I don't know how to overcome this problem. Any hint or reference?










share|cite|improve this question











$endgroup$











  • $begingroup$
    Have you tried solving the equation with $U(x,T)=g(x)$ and let $Ttoinfty$?
    $endgroup$
    – Dylan
    Apr 2 at 7:23










  • $begingroup$
    I have edited the question, now it reflects properly the problem I have.
    $endgroup$
    – Nicolas Pimentel de Souza
    Apr 2 at 14:48













1












1








1


0



$begingroup$


I have a backward parabolic equation of the form:



beginequation
W_eta + aW_xx - bW = 0
endequation



s.t.



beginequation
lim_eta rightarrow infty(x,eta) = g(x)
endequation



were $x in mathbbR$, $eta geqslant 0$, and $a,b$ are positive constants.



Applying the following transformations:



beginalign
W(x,eta) &= U(x,t)e^beta \
t &= aeta
endalign



we would get the backward heat equation below



beginequation
U_t = - U_xx
endequation



However, the transversality condition becomes a problem, since as $eta rightarrow infty$, $e^beta rightarrow infty$.



Usually, if the terminal condition is of the form



beginequation
W(x,H) = g(x)
endequation



with $H$ finite, we could "reverse" it, that is, we could apply the following transformation:



beginequation
nu = H - eta
endequation



to obtain



beginequation
-W_nu + aW_xx - bW = 0
endequation



s.t.



beginequation
W(x,0) = g(x)
endequation



which we can solve the traditional way (Fourier transform). However, as my terminal condition happens only at infinity I can't apply the reverse transformation above, thus I don't know how to overcome this problem. Any hint or reference?










share|cite|improve this question











$endgroup$




I have a backward parabolic equation of the form:



beginequation
W_eta + aW_xx - bW = 0
endequation



s.t.



beginequation
lim_eta rightarrow infty(x,eta) = g(x)
endequation



were $x in mathbbR$, $eta geqslant 0$, and $a,b$ are positive constants.



Applying the following transformations:



beginalign
W(x,eta) &= U(x,t)e^beta \
t &= aeta
endalign



we would get the backward heat equation below



beginequation
U_t = - U_xx
endequation



However, the transversality condition becomes a problem, since as $eta rightarrow infty$, $e^beta rightarrow infty$.



Usually, if the terminal condition is of the form



beginequation
W(x,H) = g(x)
endequation



with $H$ finite, we could "reverse" it, that is, we could apply the following transformation:



beginequation
nu = H - eta
endequation



to obtain



beginequation
-W_nu + aW_xx - bW = 0
endequation



s.t.



beginequation
W(x,0) = g(x)
endequation



which we can solve the traditional way (Fourier transform). However, as my terminal condition happens only at infinity I can't apply the reverse transformation above, thus I don't know how to overcome this problem. Any hint or reference?







pde heat-equation






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Apr 2 at 14:56







Nicolas Pimentel de Souza

















asked Apr 1 at 18:06









Nicolas Pimentel de SouzaNicolas Pimentel de Souza

236




236











  • $begingroup$
    Have you tried solving the equation with $U(x,T)=g(x)$ and let $Ttoinfty$?
    $endgroup$
    – Dylan
    Apr 2 at 7:23










  • $begingroup$
    I have edited the question, now it reflects properly the problem I have.
    $endgroup$
    – Nicolas Pimentel de Souza
    Apr 2 at 14:48
















  • $begingroup$
    Have you tried solving the equation with $U(x,T)=g(x)$ and let $Ttoinfty$?
    $endgroup$
    – Dylan
    Apr 2 at 7:23










  • $begingroup$
    I have edited the question, now it reflects properly the problem I have.
    $endgroup$
    – Nicolas Pimentel de Souza
    Apr 2 at 14:48















$begingroup$
Have you tried solving the equation with $U(x,T)=g(x)$ and let $Ttoinfty$?
$endgroup$
– Dylan
Apr 2 at 7:23




$begingroup$
Have you tried solving the equation with $U(x,T)=g(x)$ and let $Ttoinfty$?
$endgroup$
– Dylan
Apr 2 at 7:23












$begingroup$
I have edited the question, now it reflects properly the problem I have.
$endgroup$
– Nicolas Pimentel de Souza
Apr 2 at 14:48




$begingroup$
I have edited the question, now it reflects properly the problem I have.
$endgroup$
– Nicolas Pimentel de Souza
Apr 2 at 14:48










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