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Can the elements on the main diagonal of U be zero? If not, why?


Diagonal Matrices with Zero on DiagonalDiagonally Dominant Matrix Preserved after Gaussian Elimination (with a modification)Why do eigenvalues exclusively form the main diagonal in a diagonalizable matrix?Computing $PAQ = LU$ using Gaussian elimination with complete pivotingInverse of a matrix with main diagonal elements approaching infinityDoes encountering a zero pivot during Gaussian elimination imply that the matrix is singular?Show that the diagonal elements are not all $0$On the main diagonal of a particular matrix $(A+A^-1)^-1$Show that partial pivoting leads to an $LU$ decomposition of $PA$.LU decomposition of SPD matrix without partial pivoting?













-1












$begingroup$


Suppose that Gaussian elimination can be done on this matrix without pivoting. It results in an LU decomposition of $A$, i.e. $A=LU$. Can the elements on the main diagonal of U be zero? If not, why?










share|cite|improve this question









$endgroup$











  • $begingroup$
    If the diagonal entries of $U$ are zero, the matrix $A = LU$ will be singular, and so the matrix equation $Ax = LUx = b$ is not guaranteed to be solvable.
    $endgroup$
    – D.B.
    Mar 29 at 2:29















-1












$begingroup$


Suppose that Gaussian elimination can be done on this matrix without pivoting. It results in an LU decomposition of $A$, i.e. $A=LU$. Can the elements on the main diagonal of U be zero? If not, why?










share|cite|improve this question









$endgroup$











  • $begingroup$
    If the diagonal entries of $U$ are zero, the matrix $A = LU$ will be singular, and so the matrix equation $Ax = LUx = b$ is not guaranteed to be solvable.
    $endgroup$
    – D.B.
    Mar 29 at 2:29













-1












-1








-1





$begingroup$


Suppose that Gaussian elimination can be done on this matrix without pivoting. It results in an LU decomposition of $A$, i.e. $A=LU$. Can the elements on the main diagonal of U be zero? If not, why?










share|cite|improve this question









$endgroup$




Suppose that Gaussian elimination can be done on this matrix without pivoting. It results in an LU decomposition of $A$, i.e. $A=LU$. Can the elements on the main diagonal of U be zero? If not, why?







linear-algebra






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 29 at 2:20









dxdydzdxdydz

47610




47610











  • $begingroup$
    If the diagonal entries of $U$ are zero, the matrix $A = LU$ will be singular, and so the matrix equation $Ax = LUx = b$ is not guaranteed to be solvable.
    $endgroup$
    – D.B.
    Mar 29 at 2:29
















  • $begingroup$
    If the diagonal entries of $U$ are zero, the matrix $A = LU$ will be singular, and so the matrix equation $Ax = LUx = b$ is not guaranteed to be solvable.
    $endgroup$
    – D.B.
    Mar 29 at 2:29















$begingroup$
If the diagonal entries of $U$ are zero, the matrix $A = LU$ will be singular, and so the matrix equation $Ax = LUx = b$ is not guaranteed to be solvable.
$endgroup$
– D.B.
Mar 29 at 2:29




$begingroup$
If the diagonal entries of $U$ are zero, the matrix $A = LU$ will be singular, and so the matrix equation $Ax = LUx = b$ is not guaranteed to be solvable.
$endgroup$
– D.B.
Mar 29 at 2:29










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