Variance of Stochastic Integral $int_0^1t^2 dWt$Expected value of the stochastic integral $int_0^t e^as dW_s$Expectation and variance of this stochastic processVariance of Ito IntegralFind a process $f=f(t,W_t)$ such that another process is a martingaleStochastic Calculus - Ito decompositionIto formula - some doubtsDistribution of stochastic integralWhat are the components in the Ito Process?Representation of Ito integralCalculating Variance of the stochastic process

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Variance of Stochastic Integral $int_0^1t^2 dWt$


Expected value of the stochastic integral $int_0^t e^as dW_s$Expectation and variance of this stochastic processVariance of Ito IntegralFind a process $f=f(t,W_t)$ such that another process is a martingaleStochastic Calculus - Ito decompositionIto formula - some doubtsDistribution of stochastic integralWhat are the components in the Ito Process?Representation of Ito integralCalculating Variance of the stochastic process













0












$begingroup$


I want to find Variance of integral $int_0^1t^2 dWt$



$W_t$ is Brownian motion



What I did:



I used Ito formula and got:



$int_0^1t^2 dWt = W_1 - int_0^1 2tW_t dt$ (correct me if I'm wrong)



I do not know how to compute $int_0^1 2tW_t dt$ or compute variance for whole answer.










share|cite|improve this question











$endgroup$







  • 2




    $begingroup$
    by Ito the variance is $int_0^1 t^4 dt$
    $endgroup$
    – Math-fun
    yesterday















0












$begingroup$


I want to find Variance of integral $int_0^1t^2 dWt$



$W_t$ is Brownian motion



What I did:



I used Ito formula and got:



$int_0^1t^2 dWt = W_1 - int_0^1 2tW_t dt$ (correct me if I'm wrong)



I do not know how to compute $int_0^1 2tW_t dt$ or compute variance for whole answer.










share|cite|improve this question











$endgroup$







  • 2




    $begingroup$
    by Ito the variance is $int_0^1 t^4 dt$
    $endgroup$
    – Math-fun
    yesterday













0












0








0





$begingroup$


I want to find Variance of integral $int_0^1t^2 dWt$



$W_t$ is Brownian motion



What I did:



I used Ito formula and got:



$int_0^1t^2 dWt = W_1 - int_0^1 2tW_t dt$ (correct me if I'm wrong)



I do not know how to compute $int_0^1 2tW_t dt$ or compute variance for whole answer.










share|cite|improve this question











$endgroup$




I want to find Variance of integral $int_0^1t^2 dWt$



$W_t$ is Brownian motion



What I did:



I used Ito formula and got:



$int_0^1t^2 dWt = W_1 - int_0^1 2tW_t dt$ (correct me if I'm wrong)



I do not know how to compute $int_0^1 2tW_t dt$ or compute variance for whole answer.







stochastic-processes stochastic-calculus stochastic-integrals






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 10 hours ago







mahdi

















asked yesterday









mahdimahdi

7412




7412







  • 2




    $begingroup$
    by Ito the variance is $int_0^1 t^4 dt$
    $endgroup$
    – Math-fun
    yesterday












  • 2




    $begingroup$
    by Ito the variance is $int_0^1 t^4 dt$
    $endgroup$
    – Math-fun
    yesterday







2




2




$begingroup$
by Ito the variance is $int_0^1 t^4 dt$
$endgroup$
– Math-fun
yesterday




$begingroup$
by Ito the variance is $int_0^1 t^4 dt$
$endgroup$
– Math-fun
yesterday










1 Answer
1






active

oldest

votes


















3












$begingroup$

Expectation of Ito integral of a deterministic function wrt to a Brownian motion is $0$. Thus,



$$ mathbbVarleft[int_0^1 t^2 d W_t right]= mathbbEleft[left(int_0^1 t^2 d W_tright)^2right]$$



Applying Ito Isometry, we obtain



$$ mathbbEleft[left(int_0^1 t^2 d W_tright)^2right] = mathbbEleft[int_0^1 t^4 dtright] = int_0^1 t^4 dt = frac15 $$






share|cite|improve this answer









$endgroup$












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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3












    $begingroup$

    Expectation of Ito integral of a deterministic function wrt to a Brownian motion is $0$. Thus,



    $$ mathbbVarleft[int_0^1 t^2 d W_t right]= mathbbEleft[left(int_0^1 t^2 d W_tright)^2right]$$



    Applying Ito Isometry, we obtain



    $$ mathbbEleft[left(int_0^1 t^2 d W_tright)^2right] = mathbbEleft[int_0^1 t^4 dtright] = int_0^1 t^4 dt = frac15 $$






    share|cite|improve this answer









    $endgroup$

















      3












      $begingroup$

      Expectation of Ito integral of a deterministic function wrt to a Brownian motion is $0$. Thus,



      $$ mathbbVarleft[int_0^1 t^2 d W_t right]= mathbbEleft[left(int_0^1 t^2 d W_tright)^2right]$$



      Applying Ito Isometry, we obtain



      $$ mathbbEleft[left(int_0^1 t^2 d W_tright)^2right] = mathbbEleft[int_0^1 t^4 dtright] = int_0^1 t^4 dt = frac15 $$






      share|cite|improve this answer









      $endgroup$















        3












        3








        3





        $begingroup$

        Expectation of Ito integral of a deterministic function wrt to a Brownian motion is $0$. Thus,



        $$ mathbbVarleft[int_0^1 t^2 d W_t right]= mathbbEleft[left(int_0^1 t^2 d W_tright)^2right]$$



        Applying Ito Isometry, we obtain



        $$ mathbbEleft[left(int_0^1 t^2 d W_tright)^2right] = mathbbEleft[int_0^1 t^4 dtright] = int_0^1 t^4 dt = frac15 $$






        share|cite|improve this answer









        $endgroup$



        Expectation of Ito integral of a deterministic function wrt to a Brownian motion is $0$. Thus,



        $$ mathbbVarleft[int_0^1 t^2 d W_t right]= mathbbEleft[left(int_0^1 t^2 d W_tright)^2right]$$



        Applying Ito Isometry, we obtain



        $$ mathbbEleft[left(int_0^1 t^2 d W_tright)^2right] = mathbbEleft[int_0^1 t^4 dtright] = int_0^1 t^4 dt = frac15 $$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 15 hours ago









        MdocMdoc

        556515




        556515



























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