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Show that the dual of $min c^Tx+d^Tx^'$ and $max a^Tx+b^Tx^'$ are equivalent



The Next CEO of Stack OverflowDuality. Is this the correct Dual to this Primal L.P.?Show that the dual of the dual is the primal for a min problemHow can I derive the following dual problem?Find the dual of the lp problemLinear optimization and the dualPrimal-dual problems of LP'sWrite down the dual LP and show that $y$ is a feasible solution to the dual LP.Deriving the dual of the minimum cost flow problem.How do I derive the Dual problem of a Primal LP with equality constraints?How to find the dual of max flow using bounding?










1












$begingroup$


Show that $(1)$ can be written in the form $(2)$



$(1)$
$min c^Tx+d^Tx^'$



$operatornames.t.$



$Ax+Bx^'geq a$



$Cx+Dx^'= b$
where $x, x^' geq 0$ and



and



$(2)$ $max a^Ty+b^Ty^'$



$operatornames.t.$



$A^Ty+C^Ty^'leq c$



$By+Dy^'= d$
where $y,y^' geq 0$



My idea:



The restrictions $(1)$ can be written in the form:



$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$



Then the dual LP to $(1)$ can be written as:



$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$



$operatornames.t.$



$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$



But how do I get to writing this in the form of $(2)$



Any help is greatly appreciated.










share|cite|improve this question











$endgroup$





This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.


Looking for an answer drawing from credible and/or official sources.















  • $begingroup$
    Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
    $endgroup$
    – gerw
    Mar 28 at 11:32










  • $begingroup$
    dual of $(1)$ in the form $(2)$
    $endgroup$
    – SABOY
    Mar 28 at 11:33










  • $begingroup$
    you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
    $endgroup$
    – LinAlg
    2 days ago















1












$begingroup$


Show that $(1)$ can be written in the form $(2)$



$(1)$
$min c^Tx+d^Tx^'$



$operatornames.t.$



$Ax+Bx^'geq a$



$Cx+Dx^'= b$
where $x, x^' geq 0$ and



and



$(2)$ $max a^Ty+b^Ty^'$



$operatornames.t.$



$A^Ty+C^Ty^'leq c$



$By+Dy^'= d$
where $y,y^' geq 0$



My idea:



The restrictions $(1)$ can be written in the form:



$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$



Then the dual LP to $(1)$ can be written as:



$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$



$operatornames.t.$



$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$



But how do I get to writing this in the form of $(2)$



Any help is greatly appreciated.










share|cite|improve this question











$endgroup$





This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.


Looking for an answer drawing from credible and/or official sources.















  • $begingroup$
    Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
    $endgroup$
    – gerw
    Mar 28 at 11:32










  • $begingroup$
    dual of $(1)$ in the form $(2)$
    $endgroup$
    – SABOY
    Mar 28 at 11:33










  • $begingroup$
    you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
    $endgroup$
    – LinAlg
    2 days ago













1












1








1





$begingroup$


Show that $(1)$ can be written in the form $(2)$



$(1)$
$min c^Tx+d^Tx^'$



$operatornames.t.$



$Ax+Bx^'geq a$



$Cx+Dx^'= b$
where $x, x^' geq 0$ and



and



$(2)$ $max a^Ty+b^Ty^'$



$operatornames.t.$



$A^Ty+C^Ty^'leq c$



$By+Dy^'= d$
where $y,y^' geq 0$



My idea:



The restrictions $(1)$ can be written in the form:



$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$



Then the dual LP to $(1)$ can be written as:



$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$



$operatornames.t.$



$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$



But how do I get to writing this in the form of $(2)$



Any help is greatly appreciated.










share|cite|improve this question











$endgroup$




Show that $(1)$ can be written in the form $(2)$



$(1)$
$min c^Tx+d^Tx^'$



$operatornames.t.$



$Ax+Bx^'geq a$



$Cx+Dx^'= b$
where $x, x^' geq 0$ and



and



$(2)$ $max a^Ty+b^Ty^'$



$operatornames.t.$



$A^Ty+C^Ty^'leq c$



$By+Dy^'= d$
where $y,y^' geq 0$



My idea:



The restrictions $(1)$ can be written in the form:



$mathcalP(beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix,beginpmatrix -a \ b \ -b endpmatrix)$



Then the dual LP to $(1)$ can be written as:



$max beginpmatrix a & -b & b endpmatrix^T(y, -y)$



$operatornames.t.$



$beginpmatrix
A & -B \
C & D \
-C &-D
endpmatrix^T(y,y^')=-beginpmatrix c \ d endpmatrix$



But how do I get to writing this in the form of $(2)$



Any help is greatly appreciated.







optimization linear-programming duality-theorems






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 28 at 11:33







SABOY

















asked Mar 28 at 11:10









SABOYSABOY

592311




592311






This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.


Looking for an answer drawing from credible and/or official sources.








This question has an open bounty worth +50
reputation from SABOY ending ending at 2019-04-06 11:18:38Z">in 4 days.


Looking for an answer drawing from credible and/or official sources.













  • $begingroup$
    Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
    $endgroup$
    – gerw
    Mar 28 at 11:32










  • $begingroup$
    dual of $(1)$ in the form $(2)$
    $endgroup$
    – SABOY
    Mar 28 at 11:33










  • $begingroup$
    you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
    $endgroup$
    – LinAlg
    2 days ago
















  • $begingroup$
    Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
    $endgroup$
    – gerw
    Mar 28 at 11:32










  • $begingroup$
    dual of $(1)$ in the form $(2)$
    $endgroup$
    – SABOY
    Mar 28 at 11:33










  • $begingroup$
    you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
    $endgroup$
    – LinAlg
    2 days ago















$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32




$begingroup$
Do you want to cast (1) in the form (2) or do you want to cast the dual of (1) in the form (2)?
$endgroup$
– gerw
Mar 28 at 11:32












$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33




$begingroup$
dual of $(1)$ in the form $(2)$
$endgroup$
– SABOY
Mar 28 at 11:33












$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago




$begingroup$
you should check the dimensions, the objective of the dual has 3 coefficients in the objective but just two variables.
$endgroup$
– LinAlg
2 days ago










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