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How do I get all objects in a nested array after performing a calculation in JavaScript?

The Next CEO of Stack OverflowHow do I remove a property from a JavaScript object?How do you get a timestamp in JavaScript?How do I check if an array includes an object in JavaScript?How to insert an item into an array at a specific index (JavaScript)?How do I correctly clone a JavaScript object?How to replace all occurrences of a string in JavaScriptHow do I empty an array in JavaScript?How to check if an object is an array?How do I remove a particular element from an array in JavaScript?Find object by id in an array of JavaScript objects

I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

edited yesterday

Boann

37.4k1290121

asked yesterday

Senthil

443

where did you iterate it?

– M.Hemant
yesterday

add a comment |

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

edited yesterday

Boann

37.4k1290121

asked yesterday

Senthil

443

where did you iterate it?

– M.Hemant
yesterday

add a comment |

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

edited yesterday

Boann

37.4k1290121

asked yesterday

Senthil

443

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

javascript jquery arrays object

edited yesterday

Boann

37.4k1290121

asked yesterday

Senthil

443

edited yesterday

Boann

37.4k1290121

asked yesterday

Senthil

443

edited yesterday

Boann

37.4k1290121

edited yesterday

Boann

37.4k1290121

edited yesterday

Boann

37.4k1290121

asked yesterday

Senthil

443

asked yesterday

Senthil

443

asked yesterday

Senthil

443

where did you iterate it?

– M.Hemant
yesterday

add a comment |

where did you iterate it?

– M.Hemant
yesterday

where did you iterate it?

– M.Hemant
yesterday

add a comment |

3 Answers
3

active

oldest

votes

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

edited yesterday

answered yesterday

R3tep

8,13882962

3

doesnot match the expected output..

– Maheer Ali
yesterday

Still doesnot match expected output.

– Maheer Ali
yesterday

From where send property come. And sourceamount which is expected output and 4000 should be "4,000"

– Maheer Ali
yesterday

@MaheerAli Come from the OP example code. And thanks for "4,000"

– R3tep
yesterday

I mistyped sourceamount there was send property in old code. But now its fine so +1

– Maheer Ali
yesterday

add a comment |

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

edited yesterday

answered yesterday

Zakaria Acharki

56.4k134471

add a comment |

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

edited yesterday

answered yesterday

Francis Leigh

901313

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

edited yesterday

answered yesterday

R3tep

8,13882962

3

doesnot match the expected output..

– Maheer Ali
yesterday

Still doesnot match expected output.

– Maheer Ali
yesterday

From where send property come. And sourceamount which is expected output and 4000 should be "4,000"

– Maheer Ali
yesterday

@MaheerAli Come from the OP example code. And thanks for "4,000"

– R3tep
yesterday

I mistyped sourceamount there was send property in old code. But now its fine so +1

– Maheer Ali
yesterday

add a comment |

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

edited yesterday

answered yesterday

R3tep

8,13882962

3

doesnot match the expected output..

– Maheer Ali
yesterday

Still doesnot match expected output.

– Maheer Ali
yesterday

From where send property come. And sourceamount which is expected output and 4000 should be "4,000"

– Maheer Ali
yesterday

@MaheerAli Come from the OP example code. And thanks for "4,000"

– R3tep
yesterday

I mistyped sourceamount there was send property in old code. But now its fine so +1

– Maheer Ali
yesterday

add a comment |

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

edited yesterday

answered yesterday

R3tep

8,13882962

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

edited yesterday

answered yesterday

R3tep

8,13882962

edited yesterday

answered yesterday

R3tep

8,13882962

answered yesterday

R3tep

8,13882962

answered yesterday

R3tep

8,13882962

3

doesnot match the expected output..

– Maheer Ali
yesterday

Still doesnot match expected output.

– Maheer Ali
yesterday

From where send property come. And sourceamount which is expected output and 4000 should be "4,000"

– Maheer Ali
yesterday

@MaheerAli Come from the OP example code. And thanks for "4,000"

– R3tep
yesterday

I mistyped sourceamount there was send property in old code. But now its fine so +1

– Maheer Ali
yesterday

add a comment |

3

doesnot match the expected output..

– Maheer Ali
yesterday

Still doesnot match expected output.

– Maheer Ali
yesterday

From where send property come. And sourceamount which is expected output and 4000 should be "4,000"

– Maheer Ali
yesterday

@MaheerAli Come from the OP example code. And thanks for "4,000"

– R3tep
yesterday

I mistyped sourceamount there was send property in old code. But now its fine so +1

– Maheer Ali
yesterday

doesnot match the expected output..

– Maheer Ali
yesterday

Still doesnot match expected output.

– Maheer Ali
yesterday

From where send property come. And sourceamount which is expected output and 4000 should be "4,000"

– Maheer Ali
yesterday

@MaheerAli Come from the OP example code. And thanks for "4,000"

– R3tep
yesterday

I mistyped sourceamount there was send property in old code. But now its fine so +1

– Maheer Ali
yesterday

add a comment |

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

edited yesterday

answered yesterday

Zakaria Acharki

56.4k134471

add a comment |

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

edited yesterday

answered yesterday

Zakaria Acharki

56.4k134471

add a comment |

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

edited yesterday

answered yesterday

Zakaria Acharki

56.4k134471

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

edited yesterday

answered yesterday

Zakaria Acharki

56.4k134471

edited yesterday

answered yesterday

Zakaria Acharki

56.4k134471

answered yesterday

Zakaria Acharki

56.4k134471

answered yesterday

Zakaria Acharki

56.4k134471

add a comment |

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

edited yesterday

answered yesterday

Francis Leigh

901313

add a comment |

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

edited yesterday

answered yesterday

Francis Leigh

901313

add a comment |

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

edited yesterday

answered yesterday

Francis Leigh

901313

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

edited yesterday

answered yesterday

Francis Leigh

901313

edited yesterday

answered yesterday

Francis Leigh

901313

answered yesterday

Francis Leigh

901313

answered yesterday

Francis Leigh

901313

add a comment |

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